The Sunday Times Teasers Book 1: Challenge yourself with 100 lateral-thinking puzzles (The Sunday Times Puzzle Books)

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Also, if we label the letters in any particular orbit alternately as “odd” and “even”, then we can only transition from an “odd” position to an “even” position and vice versa. (So we can eliminate 3 more months which have a letter with both parities). If hour is 1b then day in the first display is 2c where 3 ≤ c ≤ 8. In the second display day is 2(c+1). I used the [[ Matrix.linear() ]] solver from the enigma.py library to find assignments that give non-negative points values. (Although there are no further solutions if negative values are permitted). So the youngest two are Mike and Ken (= 13 points in total), and Ivan must be Ken’s best friend (= 10 points in total).

I assumed each mixture has multiple ingredients, and as there are only 10 possible ingredients this means each must have 4 or 9.For the first display if hour is 2b it must be 23. Then day is 1c where 4 ≤ c ≤ 8 (not 9 because the second display cannot have 2 zeros). In the second display day is 1(c+1). In the revised puzzle, only the 13×13 grid is considered, so this must provide the answer. (Which makes me wonder why the puzzle has all the stuff about straightening the paperclip at all). Bo then chooses to discard the 10 of Diamonds, and is dealt 4 of Hearts (the card discarded by Jo): The program finds two grids (up to 14×14) that allow a maximal 6 square-numbered cells to be connected, shown below: How many patients come with complaints about one part of their anatomy (ears or nose or throat) only?

Although the program looks for “reasonable” solutions, it is possible there may be a line with more than 6 connections that is not found by the program).This Python program looks for sets of 4 or 9 numbers from 1 to 10 whose squares sum to a square number. We then choose 5 of these sets to form the different types of muesli made, and look for the 2 (different) unavailable ingredients. The first unavailable ingredient only allows 2 of the types to be made (these are “basic” and “fruity”) and the second only allows 1 to be made (and this is “luxury”). Initially I drew out the various grids and looked for straight lines that could connect cells. (I am assuming the wire forms a sufficiently long straight line). is the largest number of distinct products we can have, because there are 24 rearrangements of the 4 digits, but in this list each product will appear twice (as pq × rs and rs × pq). If we use variables A, B, C, D, E to correspond to the points allocated (according to mothers name), then we can allocate the first names and surnames of the cubs to the same set of variables to give us a set of simultaneous linear equations, which we can attempt to solve to give the points values.